Also the leg is grounded to obtain electrical voltage?
A small voltage is set up across the electrodes by the hearbeat/pulse . This voltage is sensed by the sensor/electrode and is fed to the input of the amplifier. [From a little more research]
How does high pass and low pass filters play a...
I understand the Driven Right Leg circuit thanks to your explaining to an extent, but why is the requirement of resistors in the places that they are placed necessary? And what values of these resistors would be suitable? High values for some? Low for others? Im not fully understanding how they...
I'm looking at this ECG circuit in particular and im having trouble analyzing it...
The ECG circuit and the driven right leg circuit to cancel out the noise.
I am a little bit confused on what exactly the r1, the op amp and r2 do...
And the values that are generally given to build...
I don't think we're learning about Taylor series, but I just don't understand how we would solve the DE...
I can probably apply to Euler's method after solving it...
Do 10 steps. Solve the problem exactly. Compute the error (Show all details).
The problems says do 10 steps, but 3-4 steps will suffice!
Problem: y(prime) = (y-x)^2
y(0) = 0
h = 0.1
I don't understand how to get the exact solution and what to do from there!
I know that,
f(x,y) =...
I don't know if this is the right place to post a question like this...but help?
Does anyone know of a good program that can be downloaded to a ti84 that can solve integrals? It doesn't have to show the steps...just an answer [that you could check while doing homework...if you don't have...
Yes. Sorry I just had a typo A = -5 and B = -1
When you evaluate -5 [lower limit] you get -1225/24
And when you evaluate the -1 [upper limit] you get 7/24
So 7/24 - (-1225/24)
You get 154/3 times the weight density.
Which is 154/3 * 62.4
= 3203.2
?
Theres no pi in this problem, correct?
So the problem is just the limits a = -1 and b = -5 and integrating (7/24)(y^2) + (2y+3)
With the water density of 62.4 lb/ft^3 outside of the integral as a constant? Correct?